Allegiant Air G41024 Flight Status Today

Domestic flight Allegiant Air G41024 takes off from Fort Wayne (FWA) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Fort Wayne International Airport at 11:37 America/Indiana/Indianapolis. The flight is expected to land at St. Petersburg-Clearwater International Airport at 14:00 America/New_York. The flight will last about 2 hours 29 minutes.

G41024 - AAY1024 Allegiant Air (G4)
FWA Fort Wayne United States
Flight FWA to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Fort Wayne International Airport
IATA: FWAICAO: KFWA
Scheduled 11:37
None 6
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 14:00
None 5
G41024 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 29 minutes
  • Flight Distance: 1468 kms / 912 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KLOU2
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Fort Wayne: Saturday 2026-04-11 19:25 PM
  • Current Time in Saint Petersburg: Saturday 2026-04-11 19:25 PM

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Allegiant Air Flight G41024 FAQs

What is the scheduled flight duration for Allegiant Air G41024 flight?

On average, nonstop flight takes 2 hour(s) 29 minutes, with the flight distance of 1468 km (912 miles).

What type of aircraft is used for the Allegiant Air G41024 flight?

All Allegiant Air G41024 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41024 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41024 is operated on Wednesday.