Firefly FY2538 Flight Status Today

International flight Firefly FY2538 takes off from Siem Reap (SAI) Cambodia to Kuala Lumpur (KUL) Malaysia. It's operated by Firefly. The plane leaves Siem Reap Angkor International Airport at 07:00 Asia/Phnom_Penh. The flight is expected to land at Kuala Lumpur International Airport at 08:00 Asia/Kuala_Lumpur. The flight will last about 0 minutes.

FY2538 - FFM2538 Firefly (FY)
SAI Siem Reap Cambodia
Flight SAI to KUL
KUL Kuala Lumpur Malaysia
Contact Airlines It may not operate on the date requested
Departure Siem Reap Angkor International Airport
IATA: SAIICAO: VDSA
Scheduled 07:00
None None
Arrival Kuala Lumpur International Airport
IATA: KULICAO: WMKK
Scheduled 08:00
None None
FY2538 Detail
  • Type: International Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 1208 kms / 750 miles
Airline
  • Firefly
  • IATA: FY
  • ICAO: FFM
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-8FZ
  • Callsign: FFM2538
  • Departure Timezone: Asia/Phnom_Penh
  • Arrival Timezone: Asia/Kuala_Lumpur
  • Current Time in Siem Reap: Friday 2026-01-02 09:35 AM
  • Current Time in Kuala Lumpur: Friday 2026-01-02 10:35 AM

Flight routes similar to Firefly FY2538

Airline Flight no Departure Arrival
Malaysia Airlines MH4683
Malaysia Airlines 		02/01/2026
11:00 		2 hours 35 minutes
14:35
Malindo Air OD8583
Malindo Air 		02/01/2026
22:30 		1 hours 45 minutes
01:45
AirAsia AK541
AirAsia 		02/01/2026
14:55 		2 hours 15 minutes
18:10

Firefly Flight FY2538 FAQs

What is the scheduled flight duration for Firefly FY2538 flight?

On average, nonstop flight takes 0 minutes, with the flight distance of 1208 km (750 miles).

What type of aircraft is used for the Firefly FY2538 flight?

All Firefly FY2538 flights are operated using Boeing 737-8FZ aircraft.