Etihad Airways EY748 Flight Status Today

International flight Etihad Airways EY748 takes off from Johannesburg (JNB) South Africa to Abu Dhabi (AUH) United Arab Emirates. It's operated by Etihad Airways. The plane leaves O.R. Tambo International Airport at 09:50 Africa/Johannesburg. The flight is expected to land at Abu Dhabi International Airport at 19:45 Asia/Dubai. The flight will last about 7 hours 55 minutes.

EY748 - ETD748 Etihad Airways (EY)
JNB Johannesburg South Africa
Flight JNB to AUH
AUH Abu Dhabi United Arab Emirates
Contact Airlines It may not operate on the date requested
Departure O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 09:50
A 15
Arrival Abu Dhabi International Airport
IATA: AUHICAO: OMAA
Scheduled 19:45
A A7
EY748 Detail
  • Type: International Flight
  • Flight Duration: 7 hours 55 minutes
  • Flight Distance: 6275 kms / 3899 miles
Airline
  • Etihad Airways
  • IATA: EY
  • ICAO: ETD
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 787-9
  • Callsign: None
  • Departure Timezone: Africa/Johannesburg
  • Arrival Timezone: Asia/Dubai
  • Current Time in Johannesburg: Friday 2026-03-20 19:45 PM
  • Current Time in Abu Dhabi: Friday 2026-03-20 21:45 PM

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Etihad Airways Flight EY748 FAQs

What is the scheduled flight duration for Etihad Airways EY748 flight?

On average, nonstop flight takes 7 hour(s) 55 minutes, with the flight distance of 6275 km (3899 miles).

What type of aircraft is used for the Etihad Airways EY748 flight?

All Etihad Airways EY748 flights are operated using Boeing 787-9 aircraft.

Which terminal the flight Etihad Airways EY748 is arriving at?

Flight Etihad Airways EY748 arrives in Abu Dhabi International Airport at Terminal A.

How many Etihad Airways EY748 flights are operated a week?

1 flights per week. The Flight Etihad Airways EY748 is operated on Sunday.