Etihad Airways EY747 Flight Status Today

International flight Etihad Airways EY747 takes off from Abu Dhabi (AUH) United Arab Emirates to Johannesburg (JNB) South Africa. It's operated by Etihad Airways. The plane leaves Abu Dhabi International Airport at 02:05 Asia/Dubai. The flight is expected to land at O.R. Tambo International Airport at 08:20 Africa/Johannesburg. The flight will last about 8 hours 14 minutes.

EY747 - ETD747 Etihad Airways (EY)
AUH Abu Dhabi United Arab Emirates
Flight AUH to JNB
JNB Johannesburg South Africa
Contact Airlines It may not operate on the date requested
Departure Abu Dhabi International Airport
IATA: AUHICAO: OMAA
Scheduled 02:05
A B13
Arrival O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 08:20
B None
EY747 Detail
  • Type: International Flight
  • Flight Duration: 8 hours 14 minutes
  • Flight Distance: 6275 kms / 3899 miles
Airline
  • Etihad Airways
  • IATA: EY
  • ICAO: ETD
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 787-9
  • Callsign: None
  • Departure Timezone: Asia/Dubai
  • Arrival Timezone: Africa/Johannesburg
  • Current Time in Abu Dhabi: Sunday 2026-01-18 03:56 AM
  • Current Time in Johannesburg: Sunday 2026-01-18 01:56 AM

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Etihad Airways Flight EY747 FAQs

What is the scheduled flight duration for Etihad Airways EY747 flight?

On average, nonstop flight takes 8 hour(s) 14 minutes, with the flight distance of 6275 km (3899 miles).

What type of aircraft is used for the Etihad Airways EY747 flight?

All Etihad Airways EY747 flights are operated using Boeing 787-9 aircraft.

Which terminal the flight Etihad Airways EY747 is arriving at?

Flight Etihad Airways EY747 arrives in O.R. Tambo International Airport at Terminal B.

How many Etihad Airways EY747 flights are operated a week?

1 flights per week. The Flight Etihad Airways EY747 is operated on Saturday.