Delta DL5887 Flight Status Today

Domestic flight Delta DL5887 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Delta Airlines. The plane leaves Cleveland Hopkins International Airport at 16:38 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 17:15 America/New_York. The flight will last about 0 minutes.

DL5887 - DAL5887 Delta Airlines (DL)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 18-March-2022
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 16:38
None None
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 17:15
4 B47
DL5887 Detail
  • Type: Domestic Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KILG1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2025-12-29 03:33 AM
  • Current Time in New York: Monday 2025-12-29 03:33 AM

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Delta Flight DL5887 FAQs

What is the scheduled flight duration for Delta DL5887 flight?

On average, nonstop flight takes 0 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Delta DL5887 flight?

All Delta DL5887 flights are operated using Embraer 175 aircraft.

Which terminal the flight Delta DL5887 is arriving at?

Flight Delta DL5887 arrives in John F. Kennedy International Airport at Terminal 4.