Delta DL4838 Flight Status Today

Domestic flight Delta DL4838 takes off from Minneapolis (MSP) United States to Cleveland (CLE) United States. It's operated by Delta Airlines. The plane leaves Minneapolis Airport at 20:26 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at 23:29 America/New_York. The flight will last about 2 hours 3 minutes.

DL4838 - DAL4838 Delta Airlines (DL)
MSP Minneapolis United States
Flight MSP to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Minneapolis Airport
IATA: MSPICAO: KMSP
Scheduled 20:26
1 A4
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 23:29
None B6
DL4838 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 3 minutes
  • Flight Distance: 1001 kms / 622 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: F-KBRY4
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Minneapolis: Saturday 2026-03-21 13:40 PM
  • Current Time in Cleveland: Saturday 2026-03-21 14:40 PM

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Delta Flight DL4838 FAQs

What is the scheduled flight duration for Delta DL4838 flight?

On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 1001 km (622 miles).

What type of aircraft is used for the Delta DL4838 flight?

All Delta DL4838 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

How many Delta DL4838 flights are operated a week?

1 flights per week. The Flight Delta DL4838 is operated on Saturday.