Delta DL4800 Flight Status Today

Domestic flight Delta DL4800 takes off from Cleveland (CLE) United States to Minneapolis (MSP) United States. It's operated by Delta Airlines. The plane leaves Cleveland Hopkins International Airport at 12:28 America/New_York. The flight is expected to land at Minneapolis Airport at 13:41 America/Chicago. The flight will last about 2 hours 13 minutes.

DL4800 - DAL4800 Delta Airlines (DL)
CLE Cleveland United States
Flight CLE to MSP
MSP Minneapolis United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 12:28
TERM B5
Arrival Minneapolis Airport
IATA: MSPICAO: KMSP
Scheduled 13:41
1 A3
DL4800 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 13 minutes
  • Flight Distance: 1001 kms / 622 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: Friday
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1.5 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: T-KLGA56
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Cleveland: Sunday 2026-01-18 12:20 PM
  • Current Time in Minneapolis: Sunday 2026-01-18 11:20 AM

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Delta Flight DL4800 FAQs

What is the scheduled flight duration for Delta DL4800 flight?

On average, nonstop flight takes 2 hour(s) 13 minutes, with the flight distance of 1001 km (622 miles).

What type of aircraft is used for the Delta DL4800 flight?

All Delta DL4800 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

Which terminal the flight Delta DL4800 is arriving at?

Flight Delta DL4800 arrives in Minneapolis Airport at Terminal 1.

How many Delta DL4800 flights are operated a week?

1 flights per week. The Flight Delta DL4800 is operated on Friday.