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Delta DL4758 Flight Status Today
Domestic flight Delta DL4758 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by Delta Airlines. The plane leaves John F. Kennedy International Airport at 15:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 17:09 America/New_York. The flight will last about 1 hours 17 minutes.
DL4758 - DAL4758
Delta Airlines (DL)
JFK
New York United States
CLE
Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 30-April-2022
DL4758 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 17 minutes
- Flight Distance: 682 kms / 424 miles
Airline
- Delta Airlines
- IATA: DL
- ICAO: DAL
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: Normal passenger
- Seats: 69
- Freight capacity: 1.9 tons
- Passenger classes: First Class, Economy, Premium Economy
More Detail
- Aircraft: Mitsubishi CRJ-900LR
- Callsign: F-KHGR1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in New York: Saturday 2026-02-07 19:32 PM
- Current Time in Cleveland: Saturday 2026-02-07 19:32 PM
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DL5018 Delta |
07/02/2026 09:54 |
2 hours 14 minutes 11:49 |
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SV6985 Saudia Airlines |
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|
CI9085 China Airlines |
07/02/2026 09:54 |
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|
QR9327 Qatar Airways |
07/02/2026 13:30 |
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|
VS2911 Virgin Atlantic |
07/02/2026 13:55 |
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|
KE7317 Korean Air |
07/02/2026 13:55 |
1 hours 54 minutes 15:49 |
|
KL6794 KLM |
07/02/2026 14:28 |
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|
KL7222 KLM |
07/02/2026 21:18 |
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Delta Flight DL4758 FAQs
What is the scheduled flight duration for Delta DL4758 flight?
On average, nonstop flight takes 1 hour(s) 17 minutes, with the flight distance of 682 km (424 miles).
What type of aircraft is used for the Delta DL4758 flight?
All Delta DL4758 flights are operated using Mitsubishi CRJ-900LR aircraft.
Which terminal the flight Delta DL4758 is arriving at?
Flight Delta DL4758 arrives in Cleveland Hopkins International Airport at Terminal TERM.
