Delta DL4758 flight status now

DL4758 - DAL4758 Delta Airlines (DL)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-April-2022
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 15:00
4 A15
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:09
TERM B6
DL4758 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 17 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 69
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Premium Economy
More Detail
  • Aircraft: Mitsubishi CRJ-900LR
  • Callsign: F-KHGR1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Tuesday 2025-11-18 07:35 AM
  • Current Time in Cleveland: Tuesday 2025-11-18 07:35 AM

Domestic flight Delta DL4758 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by Delta Airlines. The plane leaves John F. Kennedy International Airport at 15:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 17:09 America/New_York. The flight will last about 1 hours 17 minutes.

Similar flight route from New York (JFK) to Cleveland (CLE)

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Virgin Atlantic VS3149
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Qatar Airways QR9327
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Cathay Pacific CX7513
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Frequently asked questions, answered

How long is the flight from New York to Cleveland?

On average, nonstop flight takes 1 hour(s) 17 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Delta DL4758 flight?

All Delta DL4758 flights are operated using Mitsubishi CRJ-900LR aircraft.

Which terminal the flight Delta DL4758 is arriving at?

Flight Delta DL4758 arrives in Cleveland Hopkins International Airport at Terminal TERM.