Delta DL4709 Flight Status Today

Domestic flight Delta DL4709 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Delta Airlines. The plane leaves Cleveland Hopkins International Airport at 10:19 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 12:05 America/New_York. The flight will last about 1 hours 3 minutes.

DL4709 - DAL4709 Delta Airlines (DL)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-April-2022
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 10:19
TERM B6
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 12:05
4 A12
DL4709 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 3 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Mitsubishi CRJ-900LR
  • Callsign: F-KJFK2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-04-12 21:47 PM
  • Current Time in New York: Sunday 2026-04-12 21:47 PM

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Delta Flight DL4709 FAQs

What is the scheduled flight duration for Delta DL4709 flight?

On average, nonstop flight takes 1 hour(s) 3 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Delta DL4709 flight?

All Delta DL4709 flights are operated using Mitsubishi CRJ-900LR aircraft.

Which terminal the flight Delta DL4709 is arriving at?

Flight Delta DL4709 arrives in John F. Kennedy International Airport at Terminal 4.