Delta DL3428 Flight Status Today

Domestic flight Delta DL3428 takes off from Milwaukee (MKE) United States to New York (LGA) United States. It's operated by Delta Airlines. The plane leaves General Mitchell International Airport at 14:00 America/Chicago. The flight is expected to land at LaGuardia Airport at 17:15 America/New_York. The flight will last about 2 hours 32 minutes.

DL3428 - DAL3428 Delta Airlines (DL)
MKE Milwaukee United States
Flight MKE to LGA
LGA New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 02-December-2019
Departure General Mitchell International Airport
IATA: MKEICAO: KMKE
Scheduled 14:00
None D43
Arrival LaGuardia Airport
IATA: LGAICAO: KLGA
Scheduled 17:15
D D9
DL3428 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 32 minutes
  • Flight Distance: 1188 kms / 738 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: TCF3428154
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Milwaukee: Monday 2025-12-29 03:43 AM
  • Current Time in New York: Monday 2025-12-29 04:43 AM

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Delta Flight DL3428 FAQs

What is the scheduled flight duration for Delta DL3428 flight?

On average, nonstop flight takes 2 hour(s) 32 minutes, with the flight distance of 1188 km (738 miles).

What type of aircraft is used for the Delta DL3428 flight?

All Delta DL3428 flights are operated using CRJ9 aircraft.

Which terminal the flight Delta DL3428 is arriving at?

Flight Delta DL3428 arrives in LaGuardia Airport at Terminal D.