Delta DL1909 Flight Status Today

International flight Delta DL1909 takes off from Minneapolis (MSP) United States to Belize City (BZE) Belize. It's operated by Delta Airlines. The plane leaves Minneapolis Airport at 07:25 America/Chicago. The flight is expected to land at Philip S.W. Goldson International Airport at 11:00 America/Belize. The flight will last about 4 hours 9 minutes.

DL1909 - DAL1909 Delta Airlines (DL)
MSP Minneapolis United States
Flight MSP to BZE
BZE Belize City Belize
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-March-2021
Departure Minneapolis Airport
IATA: MSPICAO: KMSP
Scheduled 07:25
1 G4
Arrival Philip S.W. Goldson International Airport
IATA: BZEICAO: MZBZ
Scheduled 11:00
None GT4
DL1909 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 9 minutes
  • Flight Distance: 3066 kms / 1905 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 180
  • Freight capacity: 17.1 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-KRIC5
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Belize
  • Current Time in Minneapolis: Sunday 2026-01-11 20:45 PM
  • Current Time in Belize City: Sunday 2026-01-11 20:45 PM

Flight routes similar to Delta DL1909

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Delta Flight DL1909 FAQs

What is the scheduled flight duration for Delta DL1909 flight?

On average, nonstop flight takes 4 hour(s) 9 minutes, with the flight distance of 3066 km (1905 miles).

What type of aircraft is used for the Delta DL1909 flight?

All Delta DL1909 flights are operated using Airbus A320 aircraft.