Cathay Pacific CX7678 Flight Status Today

Domestic flight Cathay Pacific CX7678 takes off from Dallas (DFW) United States to Cleveland (CLE) United States. It's operated by Cathay Pacific. The plane leaves Dallas/Fort Worth International Airport at 18:40 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at 22:15 America/New_York. The flight will last about 2 hours 3 minutes.

CX7678 - CPA7678 Cathay Pacific (CX)
DFW Dallas United States
Flight DFW to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Dallas/Fort Worth International Airport
IATA: DFWICAO: KDFW
Scheduled 18:40
A A18
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 22:15
None C4
CX7678 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 3 minutes
  • Flight Distance: 1644 kms / 1021 miles
Airline
  • Cathay Pacific
  • IATA: CX
  • ICAO: CPA
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 700 and Challenger 870
  • Callsign: None
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Dallas: Sunday 2026-05-03 13:48 PM
  • Current Time in Cleveland: Sunday 2026-05-03 14:48 PM

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Cathay Pacific Flight CX7678 FAQs

What is the scheduled flight duration for Cathay Pacific CX7678 flight?

On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 1644 km (1021 miles).

What type of aircraft is used for the Cathay Pacific CX7678 flight?

All Cathay Pacific CX7678 flights are operated using Canadair (Bombardier) Regional Jet 700 and Challenger 870 aircraft.

How many Cathay Pacific CX7678 flights are operated a week?

1 flights per week. The Flight Cathay Pacific CX7678 is operated on Saturday.