Air Marshall Islands CW4795 Flight Status Today

Domestic flight Air Marshall Islands CW4795 takes off from Oklahoma City (OKC) United States to Chicago (ORD) United States. It's operated by Air Marshall Islands. The plane leaves Will Rogers World Airport at 16:58 America/Chicago. The flight is expected to land at O'Hare International Airport at None America/Chicago. The flight will last about 1 hours 37 minutes.

CW4795 - MRS4795 Air Marshall Islands (CW)
OKC Oklahoma City United States
Flight OKC to ORD
ORD Chicago United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 16:58
None None
Arrival O'Hare International Airport
IATA: ORDICAO: KORD
Scheduled None
None None
CW4795 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 37 minutes
  • Flight Distance: 1114 kms / 692 miles
Airline
  • Air Marshall Islands
  • IATA: CW
  • ICAO: MRS
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Mitsubishi CRJ-200LR
  • Callsign: SKW4795
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Oklahoma City: Sunday 2026-01-18 06:15 AM
  • Current Time in Chicago: Sunday 2026-01-18 06:15 AM

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Air Marshall Islands Flight CW4795 FAQs

What is the scheduled flight duration for Air Marshall Islands CW4795 flight?

On average, nonstop flight takes 1 hour(s) 37 minutes, with the flight distance of 1114 km (692 miles).

What type of aircraft is used for the Air Marshall Islands CW4795 flight?

All Air Marshall Islands CW4795 flights are operated using Mitsubishi CRJ-200LR aircraft.