Air Marshall Islands CW4745 Flight Status Today

Domestic flight Air Marshall Islands CW4745 takes off from Houston (IAH) United States to Amarillo (AMA) United States. It's operated by Air Marshall Islands. The plane leaves George Bush Intercontinental Airport at 21:44 America/Chicago. The flight is expected to land at Rick Husband Amarillo International Airport at None America/Chicago. The flight will last about 1 hours 22 minutes.

CW4745 - MRS4745 Air Marshall Islands (CW)
IAH Houston United States
Flight IAH to AMA
AMA Amarillo United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 21:44
None None
Arrival Rick Husband Amarillo International Airport
IATA: AMAICAO: KAMA
Scheduled None
None None
CW4745 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 22 minutes
  • Flight Distance: 833 kms / 517 miles
Airline
  • Air Marshall Islands
  • IATA: CW
  • ICAO: MRS
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Mitsubishi CRJ-200LR
  • Callsign: SKW4745
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Houston: Wednesday 2025-12-31 11:18 AM
  • Current Time in Amarillo: Wednesday 2025-12-31 11:18 AM

Flight routes similar to Air Marshall Islands CW4745

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Air Canada AC4645
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Air New Zealand NZ2983
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16:20 		1 hours 59 minutes
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Emirates EK6086
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United Airlines UA4821
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Air Marshall Islands Flight CW4745 FAQs

What is the scheduled flight duration for Air Marshall Islands CW4745 flight?

On average, nonstop flight takes 1 hour(s) 22 minutes, with the flight distance of 833 km (517 miles).

What type of aircraft is used for the Air Marshall Islands CW4745 flight?

All Air Marshall Islands CW4745 flights are operated using Mitsubishi CRJ-200LR aircraft.