Air Marshall Islands CW4709 Flight Status Today

Domestic flight Air Marshall Islands CW4709 takes off from Oklahoma City (OKC) United States to Denver (DEN) United States. It's operated by Air Marshall Islands. The plane leaves Will Rogers World Airport at 12:38 America/Chicago. The flight is expected to land at Denver International Airport at None America/Denver. The flight will last about 1 hours 27 minutes.

CW4709 - MRS4709 Air Marshall Islands (CW)
OKC Oklahoma City United States
Flight OKC to DEN
DEN Denver United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 12:38
None None
Arrival Denver International Airport
IATA: DENICAO: KDEN
Scheduled None
None None
CW4709 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 27 minutes
  • Flight Distance: 796 kms / 495 miles
Airline
  • Air Marshall Islands
  • IATA: CW
  • ICAO: MRS
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Mitsubishi CRJ-200LR
  • Callsign: SKW4709
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Denver
  • Current Time in Oklahoma City: Sunday 2026-03-01 15:47 PM
  • Current Time in Denver: Sunday 2026-03-01 14:47 PM

Flight routes similar to Air Marshall Islands CW4709

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Air Canada AC4128
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SkyWest Airlines OO5490
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Air Marshall Islands Flight CW4709 FAQs

What is the scheduled flight duration for Air Marshall Islands CW4709 flight?

On average, nonstop flight takes 1 hour(s) 27 minutes, with the flight distance of 796 km (495 miles).

What type of aircraft is used for the Air Marshall Islands CW4709 flight?

All Air Marshall Islands CW4709 flights are operated using Mitsubishi CRJ-200LR aircraft.