Air Marshall Islands CW4657 Flight Status Today

Domestic flight Air Marshall Islands CW4657 takes off from Amarillo (AMA) United States to Houston (IAH) United States. It's operated by Air Marshall Islands. The plane leaves Rick Husband Amarillo International Airport at 15:26 America/Chicago. The flight is expected to land at George Bush Intercontinental Airport at None America/Chicago. The flight will last about 1 hours 19 minutes.

CW4657 - MRS4657 Air Marshall Islands (CW)
AMA Amarillo United States
Flight AMA to IAH
IAH Houston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Rick Husband Amarillo International Airport
IATA: AMAICAO: KAMA
Scheduled 15:26
None None
Arrival George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled None
None None
CW4657 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 19 minutes
  • Flight Distance: 833 kms / 517 miles
Airline
  • Air Marshall Islands
  • IATA: CW
  • ICAO: MRS
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Mitsubishi CRJ-200LR
  • Callsign: SKW4657
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Amarillo: Wednesday 2025-12-31 13:22 PM
  • Current Time in Houston: Wednesday 2025-12-31 13:22 PM

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Air Marshall Islands Flight CW4657 FAQs

What is the scheduled flight duration for Air Marshall Islands CW4657 flight?

On average, nonstop flight takes 1 hour(s) 19 minutes, with the flight distance of 833 km (517 miles).

What type of aircraft is used for the Air Marshall Islands CW4657 flight?

All Air Marshall Islands CW4657 flights are operated using Mitsubishi CRJ-200LR aircraft.