JetBlue Airways B69810 Flight Status Today

Domestic flight JetBlue Airways B69810 takes off from Milwaukee (MKE) United States to Boston (BOS) United States. It's operated by JetBlue Airways. The plane leaves General Mitchell International Airport at 01:15 America/Chicago. The flight is expected to land at Logan International Airport at 04:15 America/New_York. The flight will last about 1 hours 12 minutes.

B69810 - JBU9810 JetBlue Airways (B6)
MKE Milwaukee United States
Flight MKE to BOS
BOS Boston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-January-2021
Departure General Mitchell International Airport
IATA: MKEICAO: KMKE
Scheduled 01:15
None None
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 04:15
C C6
B69810 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 12 minutes
  • Flight Distance: 1383 kms / 860 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: E190
  • Callsign: JBU9810
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Milwaukee: Sunday 2026-05-03 04:24 AM
  • Current Time in Boston: Sunday 2026-05-03 05:24 AM

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JetBlue Airways Flight B69810 FAQs

What is the scheduled flight duration for JetBlue Airways B69810 flight?

On average, nonstop flight takes 1 hour(s) 12 minutes, with the flight distance of 1383 km (860 miles).

What type of aircraft is used for the JetBlue Airways B69810 flight?

All JetBlue Airways B69810 flights are operated using E190 aircraft.

Which terminal the flight JetBlue Airways B69810 is arriving at?

Flight JetBlue Airways B69810 arrives in Logan International Airport at Terminal C.