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JetBlue Airways B69804 Flight Status Today
Domestic flight JetBlue Airways B69804 takes off from Milwaukee (MKE) United States to New York (JFK) United States. It's operated by JetBlue Airways. The plane leaves General Mitchell International Airport at 01:11 America/Chicago. The flight is expected to land at John F. Kennedy International Airport at 04:02 America/New_York. The flight will last about 2 hours 20 minutes.
B69804 - JBU9804
JetBlue Airways (B6)
MKE
Milwaukee United States
JFK
New York United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 03-January-2021
B69804 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 20 minutes
- Flight Distance: 1199 kms / 745 miles
Airline
- JetBlue Airways
- IATA: B6
- ICAO: JBU
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Milwaukee: Wednesday 2025-12-31 23:54 PM
- Current Time in New York: Thursday 2026-01-01 00:54 AM
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LY4061 El Al |
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|
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|
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JetBlue Airways Flight B69804 FAQs
What is the scheduled flight duration for JetBlue Airways B69804 flight?
On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1199 km (745 miles).