JetBlue Airways B69002 Flight Status Today

Domestic flight JetBlue Airways B69002 takes off from New York (JFK) United States to Boston (BOS) United States. It's operated by JetBlue Airways. The plane leaves John F. Kennedy International Airport at 09:45 America/New_York. The flight is expected to land at Logan International Airport at 10:28 America/New_York. The flight will last about 4 minutes.

B69002 - JBU9002 JetBlue Airways (B6)
JFK New York United States
Flight JFK to BOS
BOS Boston United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 09:45
5 524
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 10:28
5 507
B69002 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 minutes
  • Flight Distance: 300 kms / 186 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: JBU9002
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Saturday 2026-05-02 17:18 PM
  • Current Time in Boston: Saturday 2026-05-02 17:18 PM

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JetBlue Airways Flight B69002 FAQs

What is the scheduled flight duration for JetBlue Airways B69002 flight?

On average, nonstop flight takes 4 minutes, with the flight distance of 300 km (186 miles).

What type of aircraft is used for the JetBlue Airways B69002 flight?

All JetBlue Airways B69002 flights are operated using Airbus A320 (sharklets) aircraft.

Which terminal the flight JetBlue Airways B69002 is arriving at?

Flight JetBlue Airways B69002 arrives in Logan International Airport at Terminal 5.

How many JetBlue Airways B69002 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B69002 is operated on Monday.