JetBlue Airways B68607 Flight Status Today

Domestic flight JetBlue Airways B68607 takes off from Boston (BOS) United States to Jacksonville (VQQ) United States. It's operated by JetBlue Airways. The plane leaves Logan International Airport at 08:00 America/New_York. The flight is expected to land at Cecil Airport at 10:27 America/New_York. The flight will last about 2 hours 29 minutes.

B68607 - JBU8607 JetBlue Airways (B6)
BOS Boston United States
Flight BOS to VQQ
VQQ Jacksonville United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 08:00
None C7
Arrival Cecil Airport
IATA: VQQICAO: KVQQ
Scheduled 10:27
None None
B68607 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 29 minutes
  • Flight Distance: 1660 kms / 1032 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A321-231
  • Callsign: F-KCHS2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Monday 2026-01-19 15:33 PM
  • Current Time in Jacksonville: Monday 2026-01-19 15:33 PM

JetBlue Airways Flight B68607 FAQs

What is the scheduled flight duration for JetBlue Airways B68607 flight?

On average, nonstop flight takes 2 hour(s) 29 minutes, with the flight distance of 1660 km (1032 miles).

What type of aircraft is used for the JetBlue Airways B68607 flight?

All JetBlue Airways B68607 flights are operated using Airbus A321-231 aircraft.

How many JetBlue Airways B68607 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B68607 is operated on Sunday.