JetBlue Airways B68058 Flight Status Today

International flight JetBlue Airways B68058 takes off from Aruba (AUA) Aruba to New York (JFK) United States. It's operated by JetBlue Airways. The plane leaves Reina Beatrix International Airport at 12:00 America/Aruba. The flight is expected to land at John F. Kennedy International Airport at 16:25 America/New_York. The flight will last about 4 hours 2 minutes.

B68058 - JBU8058 JetBlue Airways (B6)
AUA Aruba Aruba
Flight AUA to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure Reina Beatrix International Airport
IATA: AUAICAO: TNCA
Scheduled 12:00
None 7
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 16:25
5 511
B68058 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 2 minutes
  • Flight Distance: 3140 kms / 1951 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320-232
  • Callsign: F-KJFK2
  • Departure Timezone: America/Aruba
  • Arrival Timezone: America/New_York
  • Current Time in Aruba: Thursday 2026-01-01 23:58 PM
  • Current Time in New York: Thursday 2026-01-01 22:58 PM

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JetBlue Airways Flight B68058 FAQs

What is the scheduled flight duration for JetBlue Airways B68058 flight?

On average, nonstop flight takes 4 hour(s) 2 minutes, with the flight distance of 3140 km (1951 miles).

What type of aircraft is used for the JetBlue Airways B68058 flight?

All JetBlue Airways B68058 flights are operated using Airbus A320-232 aircraft.

Which terminal the flight JetBlue Airways B68058 is arriving at?

Flight JetBlue Airways B68058 arrives in John F. Kennedy International Airport at Terminal 5.

How many JetBlue Airways B68058 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B68058 is operated on Sunday.