JetBlue Airways B66445 Flight Status Today

Domestic flight JetBlue Airways B66445 takes off from New York (JFK) United States to Jacksonville (VQQ) United States. It's operated by JetBlue Airways. The plane leaves John F. Kennedy International Airport at 08:00 America/New_York. The flight is expected to land at Cecil Airport at 14:06 America/New_York. The flight will last about 2 hours 20 minutes.

B66445 - JBU6445 JetBlue Airways (B6)
JFK New York United States
Flight JFK to VQQ
VQQ Jacksonville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 23-April-2021
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 08:00
MAIN
Arrival Cecil Airport
IATA: VQQICAO: KVQQ
Scheduled 14:06
A
B66445 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 20 minutes
  • Flight Distance: 1368 kms / 850 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 100
  • Freight capacity: 0 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Airbus A320
  • Callsign: JBU445
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Wednesday 2026-01-21 09:00 AM
  • Current Time in Jacksonville: Wednesday 2026-01-21 09:00 AM

JetBlue Airways Flight B66445 FAQs

What is the scheduled flight duration for JetBlue Airways B66445 flight?

On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1368 km (850 miles).

What type of aircraft is used for the JetBlue Airways B66445 flight?

All JetBlue Airways B66445 flights are operated using Airbus A320 aircraft.

Which terminal the flight JetBlue Airways B66445 is arriving at?

Flight JetBlue Airways B66445 arrives in Cecil Airport at Terminal A.