JetBlue Airways B64559 Flight Status Today

Domestic flight JetBlue Airways B64559 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by JetBlue Airways. The plane leaves Cleveland Hopkins International Airport at 19:07 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 20:59 America/New_York. The flight will last about 1 hours 39 minutes.

B64559 - JBU4559 JetBlue Airways (B6)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 19:07
None C9
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:59
8 41
B64559 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 39 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-02-08 06:48 AM
  • Current Time in New York: Sunday 2026-02-08 06:48 AM

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JetBlue Airways Flight B64559 FAQs

What is the scheduled flight duration for JetBlue Airways B64559 flight?

On average, nonstop flight takes 1 hour(s) 39 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the JetBlue Airways B64559 flight?

All JetBlue Airways B64559 flights are operated using Embraer 175 aircraft.

Which terminal the flight JetBlue Airways B64559 is arriving at?

Flight JetBlue Airways B64559 arrives in John F. Kennedy International Airport at Terminal 8.