JetBlue Airways B62540 Flight Status Today

Domestic flight JetBlue Airways B62540 takes off from Cleveland (CLE) United States to Boston (BOS) United States. It's operated by JetBlue Airways. The plane leaves Cleveland Hopkins International Airport at 09:50 America/New_York. The flight is expected to land at Logan International Airport at 11:38 America/New_York. The flight will last about 1 hours 48 minutes.

B62540 - JBU2540 JetBlue Airways (B6)
CLE Cleveland United States
Flight CLE to BOS
BOS Boston United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 09:50
None C6
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 11:38
C C33
B62540 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 48 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 190
  • Callsign: JBU2540
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2026-01-19 04:34 AM
  • Current Time in Boston: Monday 2026-01-19 04:34 AM

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JetBlue Airways Flight B62540 FAQs

What is the scheduled flight duration for JetBlue Airways B62540 flight?

On average, nonstop flight takes 1 hour(s) 48 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the JetBlue Airways B62540 flight?

All JetBlue Airways B62540 flights are operated using Embraer 190 aircraft.

Which terminal the flight JetBlue Airways B62540 is arriving at?

Flight JetBlue Airways B62540 arrives in Logan International Airport at Terminal C.

How many JetBlue Airways B62540 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B62540 is operated on Tuesday.