JetBlue Airways B62440 Flight Status Today

Domestic flight JetBlue Airways B62440 takes off from Cleveland (CLE) United States to Boston (BOS) United States. It's operated by JetBlue Airways. The plane leaves Cleveland Hopkins International Airport at 10:50 America/New_York. The flight is expected to land at Logan International Airport at 12:24 America/New_York. The flight will last about 1 hours 34 minutes.

B62440 - JBU2440 JetBlue Airways (B6)
CLE Cleveland United States
Flight CLE to BOS
BOS Boston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-November-2020
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 10:50
None C6
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 12:24
C C18
B62440 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 190
  • Callsign: JBU2440
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Saturday 2026-02-07 07:18 AM
  • Current Time in Boston: Saturday 2026-02-07 07:18 AM

Flight routes similar to JetBlue Airways B62440

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Icelandair FI7824
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Aer Lingus EI5363
Aer Lingus 		07/02/2026
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Delta DL5641
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KLM KL7191
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JetBlue Airways Flight B62440 FAQs

What is the scheduled flight duration for JetBlue Airways B62440 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the JetBlue Airways B62440 flight?

All JetBlue Airways B62440 flights are operated using Embraer 190 aircraft.

Which terminal the flight JetBlue Airways B62440 is arriving at?

Flight JetBlue Airways B62440 arrives in Logan International Airport at Terminal C.