JetBlue Airways B62058 Flight Status Today

Domestic flight JetBlue Airways B62058 takes off from Fort Lauderdale (FLL) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves Fort Lauderdale-Hollywood International Airport at 10:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 12:50 America/New_York. The flight will last about 2 hours 50 minutes.

B62058 - JBU2058 JetBlue Airways (B6)
FLL Fort Lauderdale United States
Flight FLL to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 10-April-2021
Departure Fort Lauderdale-Hollywood International Airport
IATA: FLLICAO: KFLL
Scheduled 10:00
3 None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 12:50
None None
B62058 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 50 minutes
  • Flight Distance: 1709 kms / 1062 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Fort Lauderdale: Thursday 2026-01-01 18:31 PM
  • Current Time in Cleveland: Thursday 2026-01-01 18:31 PM

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JetBlue Airways Flight B62058 FAQs

What is the scheduled flight duration for JetBlue Airways B62058 flight?

On average, nonstop flight takes 2 hour(s) 50 minutes, with the flight distance of 1709 km (1062 miles).