JetBlue Airways B61948 Flight Status Today

Domestic flight JetBlue Airways B61948 takes off from Las Vegas (LAS) United States to New York (JFK) United States. It's operated by JetBlue Airways. The plane leaves McCarran International Airport at 12:32 America/Los_Angeles. The flight is expected to land at John F. Kennedy International Airport at 20:53 America/New_York. The flight will last about 4 hours 59 minutes.

B61948 - JBU1948 JetBlue Airways (B6)
LAS Las Vegas United States
Flight LAS to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure McCarran International Airport
IATA: LASICAO: KLAS
Scheduled 12:32
3 D3
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:53
5 11
B61948 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 59 minutes
  • Flight Distance: 3616 kms / 2247 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A321 (sharklets)
  • Callsign: JBU1948
  • Departure Timezone: America/Los_Angeles
  • Arrival Timezone: America/New_York
  • Current Time in Las Vegas: Monday 2026-01-19 10:49 AM
  • Current Time in New York: Monday 2026-01-19 13:49 PM

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JetBlue Airways Flight B61948 FAQs

What is the scheduled flight duration for JetBlue Airways B61948 flight?

On average, nonstop flight takes 4 hour(s) 59 minutes, with the flight distance of 3616 km (2247 miles).

What type of aircraft is used for the JetBlue Airways B61948 flight?

All JetBlue Airways B61948 flights are operated using Airbus A321 (sharklets) aircraft.

Which terminal the flight JetBlue Airways B61948 is arriving at?

Flight JetBlue Airways B61948 arrives in John F. Kennedy International Airport at Terminal 5.

How many JetBlue Airways B61948 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B61948 is operated on Sunday.