JetBlue Airways B61841 Flight Status Today

Domestic flight JetBlue Airways B61841 takes off from Boston (BOS) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves Logan International Airport at 20:55 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 22:56 America/New_York. The flight will last about 2 hours 1 minutes.

B61841 - JBU1841 JetBlue Airways (B6)
BOS Boston United States
Flight BOS to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 20:55
C C29
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 22:56
None C6
B61841 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 1 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Tuesday 2026-03-03 02:57 AM
  • Current Time in Cleveland: Tuesday 2026-03-03 02:57 AM

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Korean Air KE3301
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JetBlue Airways Flight B61841 FAQs

What is the scheduled flight duration for JetBlue Airways B61841 flight?

On average, nonstop flight takes 2 hour(s) 1 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the JetBlue Airways B61841 flight?

All JetBlue Airways B61841 flights are operated using Airbus A220-300 Passenger aircraft.

How many JetBlue Airways B61841 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B61841 is operated on Wednesday.