JetBlue Airways B61541 Flight Status Today

Domestic flight JetBlue Airways B61541 takes off from Boston (BOS) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves Logan International Airport at 20:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 22:10 America/New_York. The flight will last about 1 hours 18 minutes.

B61541 - JBU1541 JetBlue Airways (B6)
BOS Boston United States
Flight BOS to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 20:00
C C23A
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 22:10
None C6
B61541 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 18 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A220-300
  • Callsign: JBU1541
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Saturday 2026-02-28 03:41 AM
  • Current Time in Cleveland: Saturday 2026-02-28 03:41 AM

Flight routes similar to JetBlue Airways B61541

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JetBlue Airways B6541
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British Airways BA8398
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Etihad Airways EY8288
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Delta DL5655
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21:31

JetBlue Airways Flight B61541 FAQs

What is the scheduled flight duration for JetBlue Airways B61541 flight?

On average, nonstop flight takes 1 hour(s) 18 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the JetBlue Airways B61541 flight?

All JetBlue Airways B61541 flights are operated using Airbus A220-300 aircraft.