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JetBlue Airways B61088 Flight Status Today
Domestic flight JetBlue Airways B61088 takes off from Fort Lauderdale (FLL) United States to Albany (ALB) United States. It's operated by JetBlue Airways. The plane leaves Fort Lauderdale-Hollywood International Airport at 21:40 29 December 2025 America/New_York. The flight is expected to land at Albany International Airport at 00:43 30 December 2025 America/New_York. The flight will last about 3 hours 3 minutes.
Current status of B61088 is Scheduled On time Estimated Depart in 12 hours, 13 minutes
- Type: Domestic Flight
- Code Shares: AD 7446
- Flight Duration: 3 hours 3 minutes
- Flight Distance: 1938 kms / 1204 miles
- JetBlue Airways
- IATA: B6
- ICAO: JBU
- Operating Days: Friday, Saturday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KBID1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Fort Lauderdale: Monday 2025-12-29 09:27 AM
- Current Time in Albany: Monday 2025-12-29 09:27 AM
JetBlue Airways Flight B61088 FAQs
What is the scheduled flight duration for JetBlue Airways B61088 flight?
On average, nonstop flight takes 3 hour(s) 3 minutes, with the flight distance of 1938 km (1204 miles).
What is the current status of JetBlue Airways B61088 flight?
The current status of flight JetBlue Airways B61088 is Scheduled On time.
What type of aircraft is used for the JetBlue Airways B61088 flight?
All JetBlue Airways B61088 flights are operated using Airbus A320 (sharklets) aircraft.
How many JetBlue Airways B61088 flights are operated a week?
2 flights per week. The Flight JetBlue Airways B61088 is operated on Friday, Saturday.
