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JetBlue Airways B61088 Flight Status Today
Domestic flight JetBlue Airways B61088 takes off from Fort Lauderdale (FLL) United States to Albany (ALB) United States. It's operated by JetBlue Airways. The plane leaves Fort Lauderdale-Hollywood International Airport at 18:55 18 January 2026 America/New_York. The flight is expected to land at Albany International Airport at 21:59 18 January 2026 America/New_York. The flight will last about 3 hours 4 minutes.
Current status of B61088 is Scheduled Delayed by 2h 59m Estimated Depart in 2 hours, 54 minutes
- Type: Domestic Flight
- Code Shares: AD 7446
- Flight Duration: 3 hours 4 minutes
- Flight Distance: 1938 kms / 1204 miles
- JetBlue Airways
- IATA: B6
- ICAO: JBU
- Operating Days: Friday, Saturday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320
- Callsign: F-KBID1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Fort Lauderdale: Sunday 2026-01-18 19:00 PM
- Current Time in Albany: Sunday 2026-01-18 19:00 PM
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JetBlue Airways Flight B61088 FAQs
What is the scheduled flight duration for JetBlue Airways B61088 flight?
On average, nonstop flight takes 3 hour(s) 4 minutes, with the flight distance of 1938 km (1204 miles).
What is the current status of JetBlue Airways B61088 flight?
The current status of flight JetBlue Airways B61088 is Scheduled Delayed by 2h 59m.
What type of aircraft is used for the JetBlue Airways B61088 flight?
All JetBlue Airways B61088 flights are operated using Airbus A320 aircraft.
How many JetBlue Airways B61088 flights are operated a week?
2 flights per week. The Flight JetBlue Airways B61088 is operated on Friday, Saturday.
