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JetBlue Airways B61085 Flight Status Today
Domestic flight JetBlue Airways B61085 takes off from Belgrade (BZN) United States to New York (JFK) United States. It's operated by JetBlue Airways. The plane leaves Bozeman Yellowstone International Airport at 22:57 America/Denver. The flight is expected to land at John F. Kennedy International Airport at 05:04 America/New_York. The flight will last about 4 hours 7 minutes.
B61085 - JBU1085
JetBlue Airways (B6)
BZN
Belgrade United States
JFK
New York United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 21-December-2021
B61085 Detail
- Type: Domestic Flight
- Flight Duration: 4 hours 7 minutes
- Flight Distance: 3061 kms / 1902 miles
Airline
- JetBlue Airways
- IATA: B6
- ICAO: JBU
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320
- Callsign: None
- Departure Timezone: America/Denver
- Arrival Timezone: America/New_York
- Current Time in Belgrade: Thursday 2026-01-01 16:29 PM
- Current Time in New York: Thursday 2026-01-01 18:29 PM
JetBlue Airways Flight B61085 FAQs
What is the scheduled flight duration for JetBlue Airways B61085 flight?
On average, nonstop flight takes 4 hour(s) 7 minutes, with the flight distance of 3061 km (1902 miles).
What type of aircraft is used for the JetBlue Airways B61085 flight?
All JetBlue Airways B61085 flights are operated using Airbus A320 aircraft.
Which terminal the flight JetBlue Airways B61085 is arriving at?
Flight JetBlue Airways B61085 arrives in John F. Kennedy International Airport at Terminal 5.
