Alitalia AZ7078 Flight Status Today

International flight Alitalia AZ7078 takes off from Rome (FCO) Italy to Belgrade (BEG) Republic of Serbia. It's operated by Alitalia. The plane leaves Leonardo da Vinci-Fiumicino Airport at 20:40 Europe/Rome. The flight is expected to land at Belgrad Nikola Tesla Airport at 22:15 Europe/Belgrade. The flight will last about 1 hours 35 minutes.

AZ7078 - AZA7078 Alitalia (AZ)
FCO Rome Italy
Flight FCO to BEG
BEG Belgrade Republic of Serbia
Contact Airlines It may not operate on the date requested
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 20:40
3 None
Arrival Belgrad Nikola Tesla Airport
IATA: BEGICAO: LYBE
Scheduled 22:15
2 None
AZ7078 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 735 kms / 456 miles
Airline
  • Alitalia
  • IATA: AZ
  • ICAO: AZA
  • Operating Days: Monday, Tuesday, Wednesday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Belgrade
  • Current Time in Rome: Tuesday 2026-01-20 18:37 PM
  • Current Time in Belgrade: Tuesday 2026-01-20 18:37 PM

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Alitalia Flight AZ7078 FAQs

What is the scheduled flight duration for Alitalia AZ7078 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 735 km (456 miles).

What type of aircraft is used for the Alitalia AZ7078 flight?

All Alitalia AZ7078 flights are operated using Airbus A319 aircraft.

Which terminal the flight Alitalia AZ7078 is arriving at?

Flight Alitalia AZ7078 arrives in Belgrad Nikola Tesla Airport at Terminal 2.

How many Alitalia AZ7078 flights are operated a week?

6 flights per week. The Flight Alitalia AZ7078 is operated on Monday, Tuesday, Wednesday, Friday, Saturday, Sunday.