Alitalia AZ7058 Flight Status Today

International flight Alitalia AZ7058 takes off from Milan (BGY) Italy to Istanbul (SAW) Turkey. It's operated by Alitalia. The plane leaves Orio al Serio International Airport at 15:30 Europe/Rome. The flight is expected to land at Sabiha Gokcen International Airport at 20:10 Europe/Istanbul. The flight will last about 2 hours 40 minutes.

AZ7058 - AZA7058 Alitalia (AZ)
BGY Milan Italy
Flight BGY to SAW
SAW Istanbul Turkey
Contact Airlines It may not operate on the date requested
Departure Orio al Serio International Airport
IATA: BGYICAO: LIME
Scheduled 15:30
None None
Arrival Sabiha Gokcen International Airport
IATA: SAWICAO: LTFJ
Scheduled 20:10
None None
AZ7058 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 40 minutes
  • Flight Distance: 1672 kms / 1039 miles
Airline
  • Alitalia
  • IATA: AZ
  • ICAO: AZA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 46
  • Freight capacity: 5.4 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Airbus A321
  • Callsign: AZA7058
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Istanbul
  • Current Time in Milan: Tuesday 2026-01-20 22:17 PM
  • Current Time in Istanbul: Wednesday 2026-01-21 00:17 AM

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Alitalia Flight AZ7058 FAQs

What is the scheduled flight duration for Alitalia AZ7058 flight?

On average, nonstop flight takes 2 hour(s) 40 minutes, with the flight distance of 1672 km (1039 miles).

What type of aircraft is used for the Alitalia AZ7058 flight?

All Alitalia AZ7058 flights are operated using Airbus A321 aircraft.

How many Alitalia AZ7058 flights are operated a week?

7 flights per week. The Flight Alitalia AZ7058 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .