Alitalia AZ7047 Flight Status Today

International flight Alitalia AZ7047 takes off from Istanbul (SAW) Turkey to Rome (FCO) Italy. It's operated by Alitalia. The plane leaves Sabiha Gokcen International Airport at 08:50 Europe/Istanbul. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 10:40 Europe/Rome. The flight will last about 2 hours 25 minutes.

AZ7047 - AZA7047 Alitalia (AZ)
SAW Istanbul Turkey
Flight SAW to FCO
FCO Rome Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-October-2019
Departure Sabiha Gokcen International Airport
IATA: SAWICAO: LTFJ
Scheduled 08:50
I
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 10:40
T3
AZ7047 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 25 minutes
  • Flight Distance: 1429 kms / 888 miles
Airline
  • Alitalia
  • IATA: AZ
  • ICAO: AZA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 177
  • Freight capacity: 17.8 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Airbus A320
  • Callsign: AZA7047
  • Departure Timezone: Europe/Istanbul
  • Arrival Timezone: Europe/Rome
  • Current Time in Istanbul: Wednesday 2026-01-21 07:20 AM
  • Current Time in Rome: Wednesday 2026-01-21 05:20 AM

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Alitalia Flight AZ7047 FAQs

What is the scheduled flight duration for Alitalia AZ7047 flight?

On average, nonstop flight takes 2 hour(s) 25 minutes, with the flight distance of 1429 km (888 miles).

What type of aircraft is used for the Alitalia AZ7047 flight?

All Alitalia AZ7047 flights are operated using Airbus A320 aircraft.

Which terminal the flight Alitalia AZ7047 is arriving at?

Flight Alitalia AZ7047 arrives in Leonardo da Vinci-Fiumicino Airport at Terminal T3.