Alitalia AZ2058 Flight Status Today

Domestic flight Alitalia AZ2058 takes off from Rome (FCO) Italy to Milan (LIN) Italy. It's operated by Alitalia. The plane leaves Leonardo da Vinci-Fiumicino Airport at 21:00 Europe/Rome. The flight is expected to land at Milano Linate Airport at 22:10 Europe/Rome. The flight will last about 1 hours 10 minutes.

AZ2058 - AZA2058 Alitalia (AZ)
FCO Rome Italy
Flight FCO to LIN
LIN Milan Italy
Contact Airlines It may not operate on the date requested
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 21:00
1 A43
Arrival Milano Linate Airport
IATA: LINICAO: LIML
Scheduled 22:10
None None
AZ2058 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 473 kms / 294 miles
Airline
  • Alitalia
  • IATA: AZ
  • ICAO: AZA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 144
  • Freight capacity: 6.7 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A320neo
  • Callsign: AZA2058
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Rome: Tuesday 2026-03-03 02:06 AM
  • Current Time in Milan: Tuesday 2026-03-03 02:06 AM

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Alitalia Flight AZ2058 FAQs

What is the scheduled flight duration for Alitalia AZ2058 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 473 km (294 miles).

What type of aircraft is used for the Alitalia AZ2058 flight?

All Alitalia AZ2058 flights are operated using Airbus A320neo aircraft.

How many Alitalia AZ2058 flights are operated a week?

6 flights per week. The Flight Alitalia AZ2058 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.