Aeromexico AM9482 Flight Status Today

International flight Aeromexico AM9482 takes off from New York (JFK) United States to Mexico City (MEX) Mexico. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 16:00 America/New_York. The flight is expected to land at Benito Juarez International Airport at 19:43 America/Mexico_City. The flight will last about 5 hours 43 minutes.

AM9482 - AMX9482 Aeromexico (AM)
JFK New York United States
Flight JFK to MEX
MEX Mexico City Mexico
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 16:00
None None
Arrival Benito Juarez International Airport
IATA: MEXICAO: MMMX
Scheduled 19:43
None None
AM9482 Detail
  • Type: International Flight
  • Flight Duration: 5 hours 43 minutes
  • Flight Distance: 3363 kms / 2090 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 9 Passenger
  • Callsign: F-KHSV4
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Mexico_City
  • Current Time in New York: Saturday 2026-02-07 08:30 AM
  • Current Time in Mexico City: Saturday 2026-02-07 07:30 AM

Flight routes similar to Aeromexico AM9482

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Korean Air KE7597
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Virgin Atlantic VS4963
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Aeromexico Flight AM9482 FAQs

What is the scheduled flight duration for Aeromexico AM9482 flight?

On average, nonstop flight takes 5 hour(s) 43 minutes, with the flight distance of 3363 km (2090 miles).

What type of aircraft is used for the Aeromexico AM9482 flight?

All Aeromexico AM9482 flights are operated using Boeing 737MAX 9 Passenger aircraft.

How many Aeromexico AM9482 flights are operated a week?

1 flights per week. The Flight Aeromexico AM9482 is operated on Sunday.