Aeromexico AM9480 Flight Status Today

Domestic flight Aeromexico AM9480 takes off from Mexico City (MEX) Mexico to Acapulco (ACA) Mexico. It's operated by Aeromexico. The plane leaves Benito Juarez International Airport at 12:05 America/Mexico_City. The flight is expected to land at Acapulco International Airport at 13:15 America/Mexico_City. The flight will last about 1 hours 10 minutes.

AM9480 - AMX9480 Aeromexico (AM)
MEX Mexico City Mexico
Flight MEX to ACA
ACA Acapulco Mexico
Contact Airlines It may not operate on the date requested
Departure Benito Juarez International Airport
IATA: MEXICAO: MMMX
Scheduled 12:05
None None
Arrival Acapulco International Airport
IATA: ACAICAO: MMAA
Scheduled 13:15
None None
AM9480 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 305 kms / 189 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KGSB1
  • Departure Timezone: America/Mexico_City
  • Arrival Timezone: America/Mexico_City
  • Current Time in Mexico City: Sunday 2026-05-03 08:13 AM
  • Current Time in Acapulco: Sunday 2026-05-03 08:13 AM

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Aeromexico Flight AM9480 FAQs

What is the scheduled flight duration for Aeromexico AM9480 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 305 km (189 miles).

What type of aircraft is used for the Aeromexico AM9480 flight?

All Aeromexico AM9480 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Aeromexico AM9480 flights are operated a week?

1 flights per week. The Flight Aeromexico AM9480 is operated on Monday.