Aeromexico AM7480 Flight Status Today

Domestic flight Aeromexico AM7480 takes off from Buenos Aires (AEP) Argentina to Tucuman (TUC) Argentina. It's operated by Aeromexico. The plane leaves Jorge Newbery Airport at 10:35 America/Argentina/Buenos_Aires. The flight is expected to land at Teniente Benjamin Matienzo Airport at 12:35 America/Argentina/Buenos_Aires. The flight will last about 2 hours 3 minutes.

AM7480 - AMX7480 Aeromexico (AM)
AEP Buenos Aires Argentina
Flight AEP to TUC
TUC Tucuman Argentina
Contact Airlines It may not operate on the date requested
Departure Jorge Newbery Airport
IATA: AEPICAO: SABE
Scheduled 10:35
TA 4
Arrival Teniente Benjamin Matienzo Airport
IATA: TUCICAO: SANT
Scheduled 12:35
None None
AM7480 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 3 minutes
  • Flight Distance: 1069 kms / 664 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 190
  • Callsign: None
  • Departure Timezone: America/Argentina/Buenos_Aires
  • Arrival Timezone: America/Argentina/Buenos_Aires
  • Current Time in Buenos Aires: Sunday 2026-04-12 06:47 AM
  • Current Time in Tucuman: Sunday 2026-04-12 06:47 AM

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Aeromexico Flight AM7480 FAQs

What is the scheduled flight duration for Aeromexico AM7480 flight?

On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 1069 km (664 miles).

What type of aircraft is used for the Aeromexico AM7480 flight?

All Aeromexico AM7480 flights are operated using Embraer 190 aircraft.

How many Aeromexico AM7480 flights are operated a week?

6 flights per week. The Flight Aeromexico AM7480 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.