Check your Flight status online
Aeromexico AM7282 Flight Status Today
International flight Aeromexico AM7282 takes off from Calgary (YYC) Canada to New York (JFK) United States. It's operated by Aeromexico. The plane leaves Calgary International Airport at 09:50 America/Edmonton. The flight is expected to land at John F. Kennedy International Airport at 16:36 America/New_York. The flight will last about 4 hours 46 minutes.
- Type: International Flight
- Flight Duration: 4 hours 46 minutes
- Flight Distance: 3284 kms / 2040 miles
- Aeromexico
- IATA: AM
- ICAO: AMX
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
- Callsign: None
- Departure Timezone: America/Edmonton
- Arrival Timezone: America/New_York
- Current Time in Calgary: Saturday 2026-03-21 21:06 PM
- Current Time in New York: Saturday 2026-03-21 23:06 PM
Flight routes similar to Aeromexico AM7282
Aeromexico Flight AM7282 FAQs
What is the scheduled flight duration for Aeromexico AM7282 flight?
On average, nonstop flight takes 4 hour(s) 46 minutes, with the flight distance of 3284 km (2040 miles).
What type of aircraft is used for the Aeromexico AM7282 flight?
All Aeromexico AM7282 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.
Which terminal the flight Aeromexico AM7282 is arriving at?
Flight Aeromexico AM7282 arrives in John F. Kennedy International Airport at Terminal 4.
How many Aeromexico AM7282 flights are operated a week?
7 flights per week. The Flight Aeromexico AM7282 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .
