Aeromexico AM5738 Flight Status Today

International flight Aeromexico AM5738 takes off from Paris (CDG) France to Rome (FCO) Italy. It's operated by Aeromexico. The plane leaves Charles de Gaulle Airport at 15:25 Europe/Paris. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 17:30 Europe/Rome. The flight will last about 1 hours 53 minutes.

AM5738 - AMX5738 Aeromexico (AM)
CDG Paris France
Flight CDG to FCO
FCO Rome Italy
Contact Airlines It may not operate on the date requested
Departure Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 15:25
2F F44
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 17:30
1 None
AM5738 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 53 minutes
  • Flight Distance: 1101 kms / 684 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: None
  • Departure Timezone: Europe/Paris
  • Arrival Timezone: Europe/Rome
  • Current Time in Paris: Monday 2026-01-19 07:01 AM
  • Current Time in Rome: Monday 2026-01-19 07:01 AM

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Aeromexico Flight AM5738 FAQs

What is the scheduled flight duration for Aeromexico AM5738 flight?

On average, nonstop flight takes 1 hour(s) 53 minutes, with the flight distance of 1101 km (684 miles).

What type of aircraft is used for the Aeromexico AM5738 flight?

All Aeromexico AM5738 flights are operated using Airbus A220-300 Passenger aircraft.

Which terminal the flight Aeromexico AM5738 is arriving at?

Flight Aeromexico AM5738 arrives in Leonardo da Vinci-Fiumicino Airport at Terminal 1.

How many Aeromexico AM5738 flights are operated a week?

7 flights per week. The Flight Aeromexico AM5738 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .