Aeromexico AM5707 Flight Status Today

International flight Aeromexico AM5707 takes off from Rome (FCO) Italy to Paris (CDG) France. It's operated by Aeromexico. The plane leaves Leonardo da Vinci-Fiumicino Airport at 09:55 Europe/Rome. The flight is expected to land at Charles de Gaulle Airport at 12:10 Europe/Paris. The flight will last about 2 hours 15 minutes.

AM5707 - AMX5707 Aeromexico (AM)
FCO Rome Italy
Flight FCO to CDG
CDG Paris France
Contact Airlines It may not operate on the date requested
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 09:55
3 None
Arrival Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 12:10
2F None
AM5707 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 15 minutes
  • Flight Distance: 1101 kms / 684 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Tuesday, Wednesday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 192
  • Freight capacity: 4.6 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Airbus A320
  • Callsign: AMX5707
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Paris
  • Current Time in Rome: Sunday 2026-02-08 16:46 PM
  • Current Time in Paris: Sunday 2026-02-08 16:46 PM

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Aeromexico Flight AM5707 FAQs

What is the scheduled flight duration for Aeromexico AM5707 flight?

On average, nonstop flight takes 2 hour(s) 15 minutes, with the flight distance of 1101 km (684 miles).

What type of aircraft is used for the Aeromexico AM5707 flight?

All Aeromexico AM5707 flights are operated using Airbus A320 aircraft.

Which terminal the flight Aeromexico AM5707 is arriving at?

Flight Aeromexico AM5707 arrives in Charles de Gaulle Airport at Terminal 2F.

How many Aeromexico AM5707 flights are operated a week?

6 flights per week. The Flight Aeromexico AM5707 is operated on Monday, Tuesday, Wednesday, Friday, Saturday, Sunday.