Aeromexico AM5618 Flight Status Today

Domestic flight Aeromexico AM5618 takes off from Cleveland (CLE) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Cleveland Hopkins International Airport at 12:50 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 14:35 America/New_York. The flight will last about 1 hours 25 minutes.

AM5618 - AMX5618 Aeromexico (AM)
CLE Cleveland United States
Flight CLE to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-August-2020
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 12:50
B
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 14:35
S
AM5618 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 25 minutes
  • Flight Distance: 893 kms / 555 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 158
  • Freight capacity: 3.1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: MD90
  • Callsign: AMX5618
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-02-08 01:38 AM
  • Current Time in Atlanta: Sunday 2026-02-08 01:38 AM

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Aeromexico Flight AM5618 FAQs

What is the scheduled flight duration for Aeromexico AM5618 flight?

On average, nonstop flight takes 1 hour(s) 25 minutes, with the flight distance of 893 km (555 miles).

What type of aircraft is used for the Aeromexico AM5618 flight?

All Aeromexico AM5618 flights are operated using MD90 aircraft.

Which terminal the flight Aeromexico AM5618 is arriving at?

Flight Aeromexico AM5618 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.