Aeromexico AM5614 Flight Status Today

Domestic flight Aeromexico AM5614 takes off from Cleveland (CLE) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Cleveland Hopkins International Airport at 08:29 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 10:15 America/New_York. The flight will last about 1 hours 46 minutes.

AM5614 - AMX5614 Aeromexico (AM)
CLE Cleveland United States
Flight CLE to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 12-September-2021
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 08:29
None B5
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 10:15
S A30
AM5614 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 46 minutes
  • Flight Distance: 893 kms / 555 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 149
  • Freight capacity: 5.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-900 (winglets) Passenger/BBJ3
  • Callsign: AMX5614
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-03-01 01:47 AM
  • Current Time in Atlanta: Sunday 2026-03-01 01:47 AM

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Aeromexico Flight AM5614 FAQs

What is the scheduled flight duration for Aeromexico AM5614 flight?

On average, nonstop flight takes 1 hour(s) 46 minutes, with the flight distance of 893 km (555 miles).

What type of aircraft is used for the Aeromexico AM5614 flight?

All Aeromexico AM5614 flights are operated using Boeing 737-900 (winglets) Passenger/BBJ3 aircraft.

Which terminal the flight Aeromexico AM5614 is arriving at?

Flight Aeromexico AM5614 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.