Aeromexico AM5608 Flight Status Today

Domestic flight Aeromexico AM5608 takes off from Baltimore (BWI) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Baltimore/Wash International Thurgood Marshall Airport at 15:52 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 17:59 America/New_York. The flight will last about 2 hours 7 minutes.

AM5608 - AMX5608 Aeromexico (AM)
BWI Baltimore United States
Flight BWI to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 20-December-2019
Departure Baltimore/Wash International Thurgood Marshall Airport
IATA: BWIICAO: KBWI
Scheduled 15:52
None D29
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 17:59
S A15
AM5608 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 7 minutes
  • Flight Distance: 929 kms / 577 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 158
  • Freight capacity: 3.1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: MD90
  • Callsign: AMX5608
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Baltimore: Friday 2026-02-27 21:27 PM
  • Current Time in Atlanta: Friday 2026-02-27 21:27 PM

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Virgin Atlantic VS2532
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Aeromexico Flight AM5608 FAQs

What is the scheduled flight duration for Aeromexico AM5608 flight?

On average, nonstop flight takes 2 hour(s) 7 minutes, with the flight distance of 929 km (577 miles).

What type of aircraft is used for the Aeromexico AM5608 flight?

All Aeromexico AM5608 flights are operated using MD90 aircraft.

Which terminal the flight Aeromexico AM5608 is arriving at?

Flight Aeromexico AM5608 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.