Aeromexico AM5498 Flight Status Today

Domestic flight Aeromexico AM5498 takes off from New York (JFK) United States to Rochester (ROC) United States. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 21:30 America/New_York. The flight is expected to land at Greater Rochester International Airport at 23:06 America/New_York. The flight will last about 1 hours 28 minutes.

AM5498 - AMX5498 Aeromexico (AM)
JFK New York United States
Flight JFK to ROC
ROC Rochester United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-April-2020
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 21:30
4 B55
Arrival Greater Rochester International Airport
IATA: ROCICAO: KROC
Scheduled 23:06
A A11
AM5498 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 28 minutes
  • Flight Distance: 424 kms / 263 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 132
  • Freight capacity: 6.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Airbus A319
  • Callsign: AMX5498
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Wednesday 2025-12-31 11:58 AM
  • Current Time in Rochester: Wednesday 2025-12-31 11:58 AM

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Aeromexico Flight AM5498 FAQs

What is the scheduled flight duration for Aeromexico AM5498 flight?

On average, nonstop flight takes 1 hour(s) 28 minutes, with the flight distance of 424 km (263 miles).

What type of aircraft is used for the Aeromexico AM5498 flight?

All Aeromexico AM5498 flights are operated using Airbus A319 aircraft.

Which terminal the flight Aeromexico AM5498 is arriving at?

Flight Aeromexico AM5498 arrives in Greater Rochester International Airport at Terminal A.