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Aeromexico AM5489 Flight Status Today
Domestic flight Aeromexico AM5489 takes off from Roanoke (ROA) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Roanoke-Blacksburg Regional Airport at 15:04 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 16:42 America/New_York. The flight will last about 1 hours 38 minutes.
AM5489 - AMX5489
Aeromexico (AM)
ROA
Roanoke United States
ATL
Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 04-January-2019
AM5489 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 38 minutes
- Flight Distance: 576 kms / 358 miles
Airline
- Aeromexico
- IATA: AM
- ICAO: AMX
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: Normal passenger
- Seats: 50
- Freight capacity: 1.5 tons
- Passenger classes: Economy, Shuttle, Premium Economy
More Detail
- Aircraft: CRJ1
- Callsign: AMX5489
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Roanoke: Saturday 2026-04-11 07:56 AM
- Current Time in Atlanta: Saturday 2026-04-11 07:56 AM
Flight routes similar to Aeromexico AM5489
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VS4903 Virgin Atlantic |
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|
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Aeromexico Flight AM5489 FAQs
What is the scheduled flight duration for Aeromexico AM5489 flight?
On average, nonstop flight takes 1 hour(s) 38 minutes, with the flight distance of 576 km (358 miles).
What type of aircraft is used for the Aeromexico AM5489 flight?
All Aeromexico AM5489 flights are operated using CRJ1 aircraft.
Which terminal the flight Aeromexico AM5489 is arriving at?
Flight Aeromexico AM5489 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.
