Aeromexico AM5451 Flight Status Today

International flight Aeromexico AM5451 takes off from New York (JFK) United States to Rome (FCO) Italy. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 20:02 America/New_York. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 10:50 Europe/Rome. The flight will last about 8 hours 48 minutes.

AM5451 - AMX5451 Aeromexico (AM)
JFK New York United States
Flight JFK to FCO
FCO Rome Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 19-April-2019
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:02
A27
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 10:50
S B36
AM5451 Detail
  • Type: International Flight
  • Flight Duration: 8 hours 48 minutes
  • Flight Distance: 6885 kms / 4278 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 293
  • Freight capacity: 10 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A330-300
  • Callsign: AMX5451
  • Departure Timezone: America/New_York
  • Arrival Timezone: Europe/Rome
  • Current Time in New York: Sunday 2026-01-18 19:59 PM
  • Current Time in Rome: Monday 2026-01-19 01:59 AM

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Aeromexico Flight AM5451 FAQs

What is the scheduled flight duration for Aeromexico AM5451 flight?

On average, nonstop flight takes 8 hour(s) 48 minutes, with the flight distance of 6885 km (4278 miles).

What type of aircraft is used for the Aeromexico AM5451 flight?

All Aeromexico AM5451 flights are operated using Airbus A330-300 aircraft.

Which terminal the flight Aeromexico AM5451 is arriving at?

Flight Aeromexico AM5451 arrives in Leonardo da Vinci-Fiumicino Airport at Terminal S.