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Aeromexico AM5449 Flight Status Today
Domestic flight Aeromexico AM5449 takes off from Columbus (CMH) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves John Glenn Columbus International Airport at 15:18 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 16:55 America/New_York. The flight will last about 1 hours 23 minutes.
- Type: Domestic Flight
- Flight Duration: 1 hours 23 minutes
- Flight Distance: 719 kms / 447 miles
- Aeromexico
- IATA: AM
- ICAO: AMX
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
- Service type: Normal passenger
- Seats: 149
- Freight capacity: 5.7 tons
- Passenger classes: Economy, Business Class, Shuttle, Premium Economy
- Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
- Callsign: AMX5449
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Columbus: Saturday 2026-02-28 07:29 AM
- Current Time in Atlanta: Saturday 2026-02-28 07:29 AM
Flight routes similar to Aeromexico AM5449
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|---|---|---|---|
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AF3051 Air France |
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VS4351 Virgin Atlantic |
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VS4349 Virgin Atlantic |
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KL5403 KLM |
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|
DL426 Delta |
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|
DL2567 Delta |
28/02/2026 08:00 |
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|
DL2469 Delta |
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|
AM3423 Aeromexico |
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Aeromexico Flight AM5449 FAQs
What is the scheduled flight duration for Aeromexico AM5449 flight?
On average, nonstop flight takes 1 hour(s) 23 minutes, with the flight distance of 719 km (447 miles).
What type of aircraft is used for the Aeromexico AM5449 flight?
All Aeromexico AM5449 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.
Which terminal the flight Aeromexico AM5449 is arriving at?
Flight Aeromexico AM5449 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.
