Aeromexico AM5449 Flight Status Today

Domestic flight Aeromexico AM5449 takes off from Columbus (CMH) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves John Glenn Columbus International Airport at 15:18 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 16:55 America/New_York. The flight will last about 1 hours 23 minutes.

AM5449 - AMX5449 Aeromexico (AM)
CMH Columbus United States
Flight CMH to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-February-2021
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 15:18
None C55
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 16:55
S B26
AM5449 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 23 minutes
  • Flight Distance: 719 kms / 447 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 149
  • Freight capacity: 5.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
  • Callsign: AMX5449
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Sunday 2025-12-28 22:43 PM
  • Current Time in Atlanta: Sunday 2025-12-28 22:43 PM

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Aeromexico Flight AM5449 FAQs

What is the scheduled flight duration for Aeromexico AM5449 flight?

On average, nonstop flight takes 1 hour(s) 23 minutes, with the flight distance of 719 km (447 miles).

What type of aircraft is used for the Aeromexico AM5449 flight?

All Aeromexico AM5449 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.

Which terminal the flight Aeromexico AM5449 is arriving at?

Flight Aeromexico AM5449 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.