Aeromexico AM5418 Flight Status Today

Domestic flight Aeromexico AM5418 takes off from Minneapolis (MSP) United States to Minot (MOT) United States. It's operated by Aeromexico. The plane leaves Minneapolis Airport at 19:30 America/Chicago. The flight is expected to land at Minot International Airport at 21:13 America/Chicago. The flight will last about 1 hours 39 minutes.

AM5418 - AMX5418 Aeromexico (AM)
MSP Minneapolis United States
Flight MSP to MOT
MOT Minot United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 12-August-2019
Departure Minneapolis Airport
IATA: MSPICAO: KMSP
Scheduled 19:30
1 B8
Arrival Minot International Airport
IATA: MOTICAO: KMOT
Scheduled 21:13
None 05
AM5418 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 39 minutes
  • Flight Distance: 724 kms / 450 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1.5 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ2
  • Callsign: AMX5418
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Minneapolis: Sunday 2026-02-08 15:42 PM
  • Current Time in Minot: Sunday 2026-02-08 15:42 PM

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Aeromexico Flight AM5418 FAQs

What is the scheduled flight duration for Aeromexico AM5418 flight?

On average, nonstop flight takes 1 hour(s) 39 minutes, with the flight distance of 724 km (450 miles).

What type of aircraft is used for the Aeromexico AM5418 flight?

All Aeromexico AM5418 flights are operated using CRJ2 aircraft.