Aeromexico AM5400 Flight Status Today

Domestic flight Aeromexico AM5400 takes off from Dulles (IAD) United States to New York (JFK) United States. It's operated by Aeromexico. The plane leaves Washington Dulles International Airport at 19:30 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 21:00 America/New_York. The flight will last about 1 hours 31 minutes.

AM5400 - AMX5400 Aeromexico (AM)
IAD Dulles United States
Flight IAD to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-July-2019
Departure Washington Dulles International Airport
IATA: IADICAO: KIAD
Scheduled 19:30
20
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 21:00
4 B48
AM5400 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 31 minutes
  • Flight Distance: 365 kms / 227 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AMX5400
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Dulles: Monday 2025-12-29 00:14 AM
  • Current Time in New York: Monday 2025-12-29 00:14 AM

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Aeromexico Flight AM5400 FAQs

What is the scheduled flight duration for Aeromexico AM5400 flight?

On average, nonstop flight takes 1 hour(s) 31 minutes, with the flight distance of 365 km (227 miles).

What type of aircraft is used for the Aeromexico AM5400 flight?

All Aeromexico AM5400 flights are operated using CRJ9 aircraft.

Which terminal the flight Aeromexico AM5400 is arriving at?

Flight Aeromexico AM5400 arrives in John F. Kennedy International Airport at Terminal 4.